SOLUTION :
First check for interior angles of a closed traverse
∠ A+∠B+∠C +∠D +∠E
= 209° 45′ +50°15’+95°15′ +102°15’+ 82° 30′
= 540°00′
The Sum of interior angle should be ( 2N-4)x 90°[ N= no of angles ]
=( 2×5-4)×90°
=540°00′
F.B Of line AB= 150°15′
interior∠B= 50°15′
F.B of Line BC= F. B of line AB + ∠B – 180°
=150°15’+50°15′-180°
=20°30′
∠C=95°15′
F.B Of line CD = F. B Of line BC + ∠C – 180°
=20°30’+95°15’+180°
=295°45′
∠D=102°15′
F. B Of Line DE = F. B Of line CD +∠D – 180°
=295°45′ + 102°15′ – 180°
=218°00′
∠E=82°30′
F. B of line EA = F. B Of line DE + ∠E – 180°
=218°00’+82°30′-180°
=120°30°
∠A=209°45′
check:
F. B Of line AB = F. B Of line EA + ∠A – 180°
=120°30’+209°45′-180°
=150°15′