The bearing of the line OP, OQ, OR, OS , OT are N30°00’E, N87°45’E, S 25°15′ E, S35°25’W and N 40°35′ W find the included angle ∠POQ,∠QOR,∠ROS,∠SOT, and∠ TOP.
SOLUTION :
∠ POQ = Bearing of OQ – bearing of OP
=87°45′- 30°00′
= 57°45′
∠ QOR = 180°-(bearing of OQ +bearing of OR)
= 180° – (87°45′ + 25°15′)
=67°00′
∠ ROS = Bearing of OR + bearing of OS
= 25°15′ +35°25′
= 60°40′
∠ SOT = 180° – ( bearing OF OS + bearing of OT )
= 180° – ( 35°25′ +40°35′)
= 104°00′
∠ TOP = Bearing of OT + bearing of OP
= 40°35′ +30°00′