Q. A simply supported beam of span 6 m carries three point loads of 60 kN, 40 kN and 70 kN at a distance of 2 m, 4 m and 6 m from left support Draw SFD and BMD. SOLUTION : Total load= 60 + 40 + 70 = 170kN Taking moments about A RB … Read more
Q. A simply supported beam of span 6 m. Three concentrated load of 10 kN, 20 kN and 30 kN are acting at 2 m, 3 m and 5 m respectively from left hand support. Draw SFD and BMD. SOLUTION: Total load = 10 + 20 + 30 = 60kN To find the reactions Taking … Read more
Q.Simply supported beam of span 8m carries three point loads of 10KN, 20 kN and 10 kN are placed at a distance of 2m, 4m and 6 m from the LHS. Draw SFD and BMD. SOLUTION: Total load = 10 + 20 + 10 = 40 KN As the given loading is symmetrical RA=RB= 40/2 … Read more
Q.A simply supported beam of span 6 m. It is carrying 2 kN, 4 kN and 6 kN at 1 m, 3 m and 5 m from the LHS. Calculate the reactions. SOLUTION: To find reactions Total load = 2 + 4 + 6= 12 kN Taking moments about A RB×6=2×1+4×3+6×5 = 2+12+ 30 = … Read more
Q. Two point loads of 2kN act at 1/3rd span points on a simply supported beam of span 6 m. Sketch the BMD and state the position of the beam where the B.M is constant and maximum. SOLUTION: As the given loading on the beam is symmetrical. Hence R{A} = R{B} = 4/2 = 2kN … Read more
Q. Draw shear force and bending moment diagrams of simply supported beam loaded as shown in figure. SOLUTION: Total load 15+10= 25 kN To find the reactions Taking moments about A RB×6 = 15×2 + 10×4 =70 RB = 70/6=11.67KN RA = 25 – 11.67 = 13.33 SFD (SHEAR FORCE DIAGRAM) F{A}= 13,33kN (same … Read more
Q. A simply supported beam of span 3 m carries two point load of 15 kN and 10 kN are acting at distances of 1 m and 2 m from left hand support. Draw SFD and BMD. Find max S.F and max В.М and indicate where it occurs. SOLUTION: To find reactions Total load= 15 … Read more
Q. A simply supported beam of span 3 m carries two point loads of each 10 kN acting at a distances of 1 m and 2 m respectively from left hand support. Draw S.F.D and B.M.D. SOLUTION: FIRST TO FIND THE REACTIONS Total load = 10 + 10 = 20kN As the load is symmetrical … Read more
Q. Calculate the support reactions for the beam given below SOLUTION: Total load = 10 + 15 = 25kN FIRST To find reactions Taking moments about A RB × 5 = 10 × 3 + 15 × 4 = 90 RB = 90/5 = 18kN RA =Total load – RB = 25 – 18 = … Read more
Q. A simply supported beam of span 7 m, carries a concentrated load of 70 kN at a distance of 3 m from right support. Draw S.F and BM diagrams. SOLUTION: Total load= 70kN Taking moments about A RB × 7 = 70 × 4 RB = (70 × 4)/7 = 40kN RA = Total … Read more