Q. A simply supported beam of span 6 m, a udl of 2 kN/m is of length 4 m acting at middle of the span. Draw S.F.D and B.M.D SOLUTION: Total load = (2 × 4) = 8 kN As the load on the beam is symmetrical Hence RA =RB = Total load / 2 … Read more
Q. A simply supported beam of span 4 m carries a udl of 2 kN/m over its left half of the span. Draw SFD and BMD. SOLUTION: Total load= 2×2=4 kN To find reactions Taking moments about A RB×4=(2×2)2/2=4 RB=4/4 = 1kN RA = Total load – RB = 4 – 1 = 3kN SFD … Read more
Q. Calculate the max bending moment for a simply supported beam with udl of 2 kN/m throughout its span. Length of beam is 4 m. SOLUTION: Given loading on the beam is Symmetrical hence RA = RB= 4 × 2 /2= 4kN BMD (BENDING MOMENT DIAGRAM) MA = MB = 0 MC = 4 × … Read more
Q.A Simply supported beam of span 4 m is carrying a udl of 10 kN/m on entire span. Draw SFD and BMD. SOLUTION: The load on the beam is symmetrical RA = RB = (10 × 4)/2 = 20kN SFD (SHEAR FORCE DIAGRAM) F{A} = 20kN F{C} = 0kN F{B} = – 20 kN Max … Read more
Q. A simply supported beam of span 6 m subjected to a udl of 2 kN/m over the entire span. Find the support reactions. SOLUTION: Total load= 6 × 2 = 12kN As the given loading is symmetrical hence RA =RB = Total load / 2 = 12/2 = 6kN . Q. … Read more
Q. simply supported beam of span 6 m carrying concentrated loads of 30KN, 20 kN, 30 kN and 20 kN at distances of 1 m, 2 m, 3m and 4 m from L.H.S. Find the supported reactions. SOLUTION: To find reactions : Total load = 30 + 20 + 30 + 20 = 100 kN … Read more
Q. A simply supported beam of span 10 m is loaded with concentrated loads of 20 kN, 40 kN and 20 kN at 2 m, 5 m and 8 m from left support respectively. Draw S.F.D and BMD and mark the values at salient points. SOLUTION: Total load = 20 + 40 + 20 = … Read more
Q. A simply supported beam 8 m long carries point loads of 10 kN, 8 kN and 6 kN at distances of 2 m, 5 m and 6 m respectively from the left support. Draw SF and BM diagrams. SOLUTION: Total load = 10 + 8 + 6 = 24kN To find reactions Taking moments … Read more
Q. A horizontal beam of 12 m long simply supported at its end, it is subjected to vertical loads of 10 kN, 20 kN and 25 kN at 3 m, 7 m and 10 m from left support respectively. Draw shear force and bending moment diagrams indicating values at salient points. SOLUTION: Total load = … Read more
Q. A simply supported beam of span 5 m three concentrated loads 10 kN, 15 kN and 10 kN are acting at 1 m, 3 m and 4 m respectively from left hand support. Find the reactions. SOLUTION: Total load = 10 + 25 + 10 = 45 kN To find the reactions Taking moments … Read more