A simply supported beam of span 4 m carries a udl of 10 kN/m over the entire span and a point load of 10 kN acting at distance of 1m from let end. Find the reactions at supports.
SOLUTION : Total load = 10 x 4 + 10 = 50 Taking moments about A RB x 4 = 10 x 1 + ( 10×4 ) 4/2 RB x 4 = 90kN RB = 90 / 4 = 22.5kN RA= Total load – RB RA= 50 – 22.5 = 27.5kN ( or ) Taking … Read more