Q. Draw the sketch of a beam of 9 m length simply supported at the left end and at 6 m from the left end. It carries a udl 5kN / m over the supported length and a concentrated load of 10 kN at the extreme right end. SOLUTION: Total load – 5 * 6 … Read more
SOLUTION: Total load= 10 + 5 * 2 = 20kN To find reactions Taking moments about A R{B} * 6 = 10 * 3 + (5 * 2)(2/2 + 6) = 30 + 70 = 100 R{B} = 100/6 = 16.67kN R{A} = 20 – 16.67 = 3.33kN SFD ( SHEAR FORCE DIAGRAM) F{A} = … Read more
SOLUTION: Total load= 10 * 3 + 3 + 6 + 5 = 44 kN To find the reactions Taking moments about A R{B} * 8 = 5 * 11 + 6 * 7 + 3 * 5 + (10 * 3) 3/2 = 55 + 42 + 15 + 45 = 157 R{B} = … Read more
SOLUTION: Total load = 20+40+20+5×3 = 95kN Taking moment about A RB × 4+20×1= 40×1+20×5 +(5×3)(3/2+2) RB×4 = 40+100+ 52.5 – 20 = 172.5 RB= 172.5/4 = 43.125kN RA = total load – RB = 95 – 43.125 = 51.875kN
Q.A over hanging beam of length 6m is simply supported on a Span 4m with an over hang of 2m in the right hand Portion. It carries a udl of 10 kn/m on a length of 4m From LHS and a two point load of 10kN and 20kN at the distance of 2m and 6m … Read more