Q. At a point of layer of oil, the shear stress is 0.2 N/m² and velocity gradient is 0.25 m/sec/m. Calculate the coefficient of dynamic.
Q. At a point of layer of oil, the shear stress is 0.2 N/m² and velocity gradient is 0.25 m/sec/m. Calculate the coefficient of dynamic. SOLUTION: Shear stress τ= 0.2N / (m ^ 2) Velocity gradient, (dv)/(dy) =0.25 m/sec/m From the relationship, τ=μ * dv/dy 0.2 = μ * 0.25 μ = 0.8N -sec/m^ 2 … Read more