Q. A simply supported beam of span 8 m carries point loads of 10 kN, 30 kN and 20 kN at 2 m, 5 m and 7 m respectively from its LHS in addition to a udl of 7.5 kN/m over its entire length. Construct SF and BM diagrams and state the position and Magnitude of max. В.М.
SOLUTION: Load load = 10 + 30 + 20 + 7.5 * 8 = 120kN To find reactions R{B} * 8 = (7.5 * 8) 8/2 + 10 * 2 + 30 * 5 + 20 * 7 R{B} = 550/8 = 68.75kN R{A} = 120 – 68.75 = 51.25kN SFD ( SHEAR FORCE DIAGRAM) … Read more