Q. A simply supported beam of span 8 m, carries a udl of 20kN / m upto a distance of 4 m from left support and a concentrated load of 40 kN at a distance of 2 m from right support. Draw SFD and BMD.
SOLUTION: Total load 20 * 4 + 40 = 120kN To find the reactions Taking moments about A R{B} * 8 = 40 * 6 + (20 * 4) * 4/2 = 240 + 160 = 400 R{B} = 400/8 = 50kN R A =Total load – R{B} = 120 – 50 = 70kN SFD … Read more