Q.A Simply Supported beam of length 4 m carries two point loads of 50 kN and 100 kN are placed at a distance of 1 m and 3 m from the left hand support. Find the reactions.
SOLUTION : Total load =50+100= 150kN Taking moments about A RB x 4 = 50 x 1 + 100 x 3 RB x 4 = 350 RB= 350/4 = 87.5kN RA= Total load – RB RA= 150 – 87.5 = 62.5kN ( or) Taking moments about B RA x 4 = 100×1 +50×3 RA … Read more