Q. A beam of length 4 m. It is supported at 1 m and 3 m from left end of the beam. A udl 2 kN/m is acting on complete length Find the reactions.

Q. A beam of length 4 m. It is supported at 1 m and 3 m from left end of the beam. A udl 2 kN/m is acting on complete length Find the reactions. SOLUTION: Total load = 2 * 4 = 8kN As beam and loading is symmetrical Hence R A =R B = … Read more

Q. A beam 8 m long carries an udl of 2kN / m on the entire span. The beam has an overhang of 1 m and 1.5 m after left hand support and right hand support respectively. The spacing between the supports is 5.5 m. Draw the SFD and BMD indicating the values at salient points.

SOLUTION: Total load= 8 * 2 = 16kN To find the reactions Taking moments about A R{B} * 5.5 + (2 * 1) * 1/2 = (2 * 7) * 7/2 R{B} = (49 – 1)/5.5 = 8.727kN R{A} = 16 – 8.727 = 7.273kN SFD(SHEAR FORCE DIAGRAM) F{D} = F{C} = 0 F{A} (just … Read more

Q. Draw SFD and BMD for the double over hanging beam as shown in figure

Q. Draw SFD and BMD for the double over hanging beam as shown in figure SOLUTION: Total load = 5 + 20 + 15 + 10 = 50kN To find the reactions Taking moments about A R{B} * 7 = 20 * 2 + 15 * 5 + 10 * 8.5 – 5 * 1 … Read more