cantilever beam subjected to combination point loads and udl loads

Q. A cantilever beam 5 m long is loaded with udl of 3kN / m over 2 m length from free end. Point load of each 5 kN are acting at 2 m and 4 m respectively from fixed end. Draw the shear force and bending moment diagrams. Mention max SF and BM values.

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Q. A cantilever beam 5 m long is loaded with udl of 3kN / m over 2 m length from free end. Point load of each 5 kN are acting at 2 m and 4 m respectively from fixed end. Draw the shear force and bending moment diagrams. Mention max SF and BM values. SOLUTION: … Read more

Q. Draw shear force and bending moment diagrams of cantilever beam loaded as shown in figure.

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Q. Draw shear force and bending moment diagrams of cantilever beam loaded as shown in figure. SOLUTION: SFD (SHEAR FORCE DIAGRAM) Total load = 4 + 5 + 3 + 4 × 2 = 20kN F{E} = 0 F{D} = 11kN(4 × 2 + 3 = 11kN) F{C} = 16kN(5 + 3 + (4 × … Read more

Q. Calculate the maximum shear force and bending moment for cantilever beam of span 3 m and carries an udl of 2kN / m over length of 1m from free end and a point load of 10 kN is acting at distance of 1 m from fixed end.

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Q. Calculate the maximum shear force and bending moment for cantilever beam of span 3 m and carries an udl of 2kN / m over length of 1m from free end and a point load of 10 kN is acting at distance of 1 m from fixed end. SOLUTION: SFD (SHEAR FORCE DIAGRAM) Total load= … Read more

Q. A cantilever beam of length 4 m is loaded as shown in figure. draw. SF and BM diagrams.

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Q. A cantilever beam of length 4 m is loaded as shown in figure. draw. SF and BM diagrams. SOLUTION :                                            Total load =30+20+10×2 = 70 kN SFD (SHEAR FORCE DIAGRAM) FA =70 kN … Read more

Q. Draw S.F.D for the cantilever shown in Figure.

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Q. Draw S.F.D for the cantilever shown in Figure. SOLUTION: Total load = 3×1 + 4 + 3×1 = 10 kN SFD ( SHEAR FORCE DIAGRAM) FE=10kN FD=7kN (same in DC) FC (just left of C) = 7 kN FC (just right of C)=3 KN FB =3kN FA =0kN MAX SHEAR FORCE occurs at A=10kN … Read more

Q. A cantilever beam of span 4 m carrier a udl of 12kN / m upto 3 m from fixed end and carries two concentrated loads 15 kN at free end and 20 kN at distance of 1m from free end. Draw SF and BM diagrams

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Q. A cantilever beam of span 4 m carrier a udl of 12kN / m upto 3 m from fixed end and carries two concentrated loads 15 kN at free end and 20 kN at distance of 1m from free end. Draw SF and BM diagrams SOLUTION : Total load= 12 × 3 + 20 … Read more

Q. A cantilever beam of span 3 m carries a two point loads of 20 kN and 30 kN at free end and centre respectively. In addition there will be a udl of 12 kN/m over the span of 1.5 m from the free end. Draw the SFD and BMD.

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Q. A cantilever beam of span 3 m carries a two point loads of 20 kN and 30 kN at free end and centre respectively. In addition there will be a udl of 12 kN/m over the span of 1.5 m from the free end. Draw the SFD and BMD. SOLUTION: Total load = 30+20 … Read more

Q. Calculate the max shear force and bending moment for a cantilever beam of span 3 m carries a udl of 5 kNm over a length of 1 m from free end and a point load of 10 kN is acting at a distance of 1 m from fixed end.

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Q. Calculate the max shear force and bending moment for a cantilever beam of span 3 m carries a udl of 5 kNm over a length of 1 m from free end and a point load of 10 kN is acting at a distance of 1 m from fixed end. SOLUTION: Total load= 10 + … Read more

Q. Draw the S.F and B.M diagrams for the cantilever beam shown in figure.

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Q. Draw the S.F and B.M diagrams for the cantilever beam shown in figure. SOLUTION: Total load = 25+18+10×4 = 83 kN SFD (SHEAR FORCE DIAGRAM ) FA = 83 kN (same in AC) FC= (just left of c) = 83 kN FC =(just right of (c)=58kN FD = 58kN FE =( just left of … Read more

Q. Cantilever beam of length 4.2 m is loaded. Draw the shear force and bending moment diagram.

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Q. Cantilever beam of length 4.2 m is loaded. Draw the shear force and bending moment diagram. SOLUTION: Total load= 30 + 20 + 12 * 3 = 86kN S.F.D ( SHEAR FORCE DIAGRAM) FA= 20kN FB = 86 kN (30+20+12×3= 86 kN) FC = 86kN(30 + 20 + 12 × 3 = 86kN) Max … Read more