A simply supported beam of span 6 m. A udl of 2 kN/m is acting on the right half of the span. A point load of 10 kN is at 2 m from the LHS. Draw SFD and BMD.

Q. A simply supported beam of span 6 m. A udl of 2 kN/m is acting on the right half of the span. A point load of 10 kN is at 2 m from the LHS. Draw SFD and BMD.

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SOLUTION: Total load = 10 + 2 * 3 = 16 kN To find reactions Taking moments about B R{A} * 6 = 10 * 4 + (2 * 3) * 3/2 = 49 R{A} = 49/6 = 8.17kN R{B} = 16 – 8.17 = 7.83kN SFD( SHEAR FORCE DIAGRAM) F{A} = 8.17kN F{B} = … Read more