Q. Draw the sketch of a beam of 9 m length simply supported at the left end and at 6 m from the left end. It carries a udl 5kN / m over the supported length and a concentrated load of 10 kN at the extreme right end.

Q. Draw the sketch of a beam of 9 m length simply supported at the left end and at 6 m from the left end. It carries a udl 5kN / m over the supported length and a concentrated load of 10 kN at the extreme right end.

SOLUTION:

Total load – 5 * 6 + 10 = 40kN
To find reactions
Taking moments about A
R{B} * 6 = (5 * 6) * 6/2 + 10 * 9
= 90 + 90 = 180
R{B} = 180/6 = 30kN
R{A} = 40 – 30 = 10kN
(or)
Taking moments about B
R{A} * 6 + 10 * 3 = (5 * 6) * 6/2 = 90
R{A} = 60/6 = 10kN

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