Q. A simply supported beam of span 5 m is carrying a udl of 2kN / m is acting from 0 m to 3 m from LHS and a point load of 4 kN is a acting at 1 m from RHS. Find the reactions.

SOLUTION:

To find reactions
Total load= (2 * 3) + 4 = 10kN
Taking moments about A
R{B} * 5 = 4 * 4 + (2 * 3) * 3/2
R{B} = (16 + 9)/5 = 25/5 = 5kN
R A =Total load – R{B} = 10 – 5 = 5kN
(or)
Taking moments about B
R{A} * 5 = 4 * 1 + (2 * 3)(3/2 + 2)
= 4 + 21 = 25kN
R{A} = 25/5 = 5kN