Q. A simply supported beam of 8 m span carries a udl of 2 kN/m over left half of the span and two concentrated loads of 2 kN and 3 kN are placed at a distance of 5 m and 6 m respectively from left support. Determine the support reactions.

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Q. A simply supported beam of 8 m span carries a udl of 2 kN/m over left half of the span and two concentrated loads of 2 kN and 3 kN are placed at a distance of 5 m and 6 m respectively from left support. Determine the support reactions.

SOLUTION:

Total load = 2 * 4 + 2 + 3 = 13kN
To find reactions
Taking moments about A
R{B} * 8 = (2 * 4) * 4/2 + 2 * 5 + 3 * 6
= 16 + 10 + 18 = 44
R{B} = 44/8 = 5.5kN
RA =Total load – R_{B} = 13 – 5.5 = 7.5kN
(or)
Taking moments about B
R{A} * 8 = 3 * 2 + 2 * 3 + (2 * 4)[4/2 + 4]
= 6 + 6 + 48 = 60
R{A} = 60/8 = 7.5kN
.. Reactions
R{A} = 7.5kN
R{B} = 5.5kN

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