Determine the viscosity of a liquid having kinematic viscosity 6 stokes and specific gravity 1.9.

by

Q. Determine the viscosity of a liquid having kinematic viscosity 6 stokes and specific gravity 1.9. SOLUTION: Kinematic viscosity u = 6 stokes = 6cm²/ s = 6 * 10-⁴m²/ s Sp. Gravity of liquid = Density of liquid/Density of water 1.9=Density of liquid/ 1000 Density of liquid= 1000×1.9=1900kg / (m³) . Using the relations … Read more

Q. Find the kinematic viscosity of an oil having density 981 kg / (m ^ 3) . The shear stress at a point in oil is 0.2452N / (m ^ 2) and velocity gradient at that point is 0.2 per second.

by

 Q. Find the kinematic viscosity of an oil having density 981 kg / (m ^ 3) . The shear stress at a point in oil is 0.2452N / (m ^ 2) and velocity gradient at that point is 0.2 per second. SOLUTION: Mass density,rho = 981kg / (m³) Shear stress, τ = 0.2452N / (m²) … Read more

Two horizontal plates are placed 1.25 cm apart, the space between them being filled with oil of viscosity 14 poises. Calculate the shear stress in oil if upper plate is moved with a velocity of 2.5 m/s.

by

 Q. Two horizontal plates are placed 1.25 cm apart, the space between them being filled with oil of viscosity 14 poises. Calculate the shear stress in oil if upper plate is moved with a velocity of 2.5 m/s. SOLUTION: Given: Distance between plates, dy 1.25 cm = 0.0125 m Viscosity μ = 14 poise = … Read more

Determine the intensity of shear of an oil having viscosity = 1 poise. The oil is used for lubricating the clearance between a shaft of diameter 10 cm and its journal bearing. The clearance is 1.5 mm and the shaft rotates at 150 rpm

by

 Q. Determine the intensity of shear of an oil having viscosity = 1 poise. The oil is used for lubricating the clearance between a shaft of diameter 10 cm and its journal bearing. The clearance is 1.5 mm and the shaft rotates at 150 rpm SOLUTION: Given: μ= 1 poise- 10 Ns/m² Dia of shaft … Read more

Q. If the equation of a velocity profile over a plate is V = 2 y2/3, in which ‘v’ is the velocity in mis at a distance of ‘y’ metres above the plate, Determine the shear stress at y = 0 and y = 0.075m (or) 7.5 сm.

by

Q. If the equation of a velocity profile over a plate is V = 2 y2/3, in which ‘v’ is the velocity in mis at a distance of ‘y’ metres above the plate, Determine the shear stress at y = 0 and y = 0.075m (or) 7.5 сm. Given: µ = 0.835 N.S/m² SOLUTION: The … Read more

Q. A liquid empressed in a cylinder has a volume of 0.0113 m³ at 0.87 * 10 ^ 6 * N / (m ^ 2) pressure and a volume of 0.0112 m³ at 13.73 * 10 ^ 6 * N / (m ^ 2) pressure. What is its bulk modulus?

by

Q. A liquid empressed in a cylinder has a volume of 0.0113 m³ at 6.87 * 10-⁶ N / (m ^ 2) pressure and a volume of 0.0112 m³ at 13.73 * 10⁶ * N /M² pressure. What is its bulk modulus? SOLUTION: Bulk modulus K =- dp/ (du/ V) dp = (13.73 * 10⁶ … Read more

Q. Estimate the capillary rise or depression in a tube of 3 mm diameter when tube is immersed in (a) Water (b) Mercury. Surface tensions for water and mercury at 20º C are 0.075 N/m & 0.52 N/m respectively.

by

Q. Estimate the capillary rise or depression in a tube of 3 mm diameter when tube is immersed in (a) Water (b) Mercury. Surface tensions for water and mercury at 20º C are 0.075 N/m & 0.52 N/m respectively. SOLUTION: Capillary rise or depression h = (2σ * cosθ)/(wr) a) In Case of Water : … Read more

Q. If liquid pressure is increased from 4000 kN/m² to (b) Ir 6000 kN/m², the volume of liquid decreased by 0.2 percent, Determine the bulk modulus of elasticity of the liquid.

by

Q. If liquid pressure is increased from 4000 kN/m² to (b) Ir 6000 kN/m², the volume of liquid decreased by 0.2 percent, Determine the bulk modulus of elasticity of the liquid. SOLUTION: Bulk modulus of elasticity K = – (dp)/((dv)/v) Change in pressure p = 6000 – 4000 = 2000kN / (m ^ 2) =(dv)/v … Read more

The specific gravity and dynamic viscosity of a certain liquid are 4.0 and 1.4N- S/ (m ^ 2) respectively. Calculate the kinematic viscosity of the liquid.

by

Q. The specific gravity and dynamic viscosity of a certain liquid are 2.0 and 1.3N- S/ (m ^ 2) respectively. Calculate the kinematic viscosity of the liquid. SOLUTION: Kinematic viscosity = μ/ρ Dynamic viscosity μ= 1.3 N- S / (m ^ 2) Specific gravity S = 2.0 Specific gravity= specific weight of liquid/ specific weight … Read more

Q. At a point of layer of oil, the shear stress is 0.2 N/m² and velocity gradient is 0.25 m/sec/m. Calculate the coefficient of dynamic.

by

Q. At a point of layer of oil, the shear stress is 0.2 N/m² and velocity gradient is 0.25 m/sec/m. Calculate the coefficient of dynamic. SOLUTION: Shear stress τ= 0.2N / (m ^ 2) Velocity gradient, (dv)/(dy) =0.25 m/sec/m From the relationship, τ=μ * dv/dy 0.2 = μ * 0.25 μ = 0.8N -sec/m^ 2 … Read more