GEOMETRICAL CONSTRUCTIONS — TO DIVIDE A LINE INTO ANY NUMBER OF EQUAL PARTS

TO DIVIDE A LINE INTO ANY NUMBER OF EQUAL PARTS

Q. Divide a line of 40 mm length into five equal parts and mark on it 3:2;

Solution:

Let AB be the given line of length 40 mm to be divided into say, five equal parts, Drave a light construction line AC at any converted to mark successively five equal divisions of any convenient length, or, place a scale along AC with its zero at A as shown in Fig. Then mark the division points as 1′,2′,3′,4’&5′ on AC.

Connect the last division point, i.e., fifth to the point B and then through the points 4′,3′,2′ and 1′ draw lines parallel to the line B5 to intersect the line AB at points 4, 3, 2, and 1 as shown in Fig. Thus the line AB is divided into five equal parts. Mark on it the ratio of 3: 2 as shown in Fig B of .

Q. Bisect an angle of 55°

Solution:
Refer the following procedure. Draw lines OA and OB at the given acute or abtuse angle. To bisect the angle AOB, with centres O and any convenient radius, draw an arc to cut the two lines at A and B. With centres A and B and same as radius, draw two arcs to intersect each other at C. Join C which bisects the given angle as in Fig.

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