Q. A simply supported beam of span 3 m carries two point load of 15 kN and 10 kN are acting at distances of 1 m and 2 m from left hand support. Draw SFD and BMD. Find max S.F and max В.М and indicate where it occurs. SOLUTION: To find reactions Total load= 15 … Read more
Q. A simply supported beam of span 3 m carries two point loads of each 10 kN acting at a distances of 1 m and 2 m respectively from left hand support. Draw S.F.D and B.M.D. SOLUTION: FIRST TO FIND THE REACTIONS Total load = 10 + 10 = 20kN As the load is symmetrical … Read more
Q. Calculate the support reactions for the beam given below SOLUTION: Total load = 10 + 15 = 25kN FIRST To find reactions Taking moments about A RB × 5 = 10 × 3 + 15 × 4 = 90 RB = 90/5 = 18kN RA =Total load – RB = 25 – 18 = … Read more
Q. A simply supported beam of span 7 m, carries a concentrated load of 70 kN at a distance of 3 m from right support. Draw S.F and BM diagrams. SOLUTION: Total load= 70kN Taking moments about A RB × 7 = 70 × 4 RB = (70 × 4)/7 = 40kN RA = Total … Read more
Q. A simply supported beam of span 4 m carries a point load of 10 kN at a distance of 1 m from left hand support, Draw SFD. and B.MD. SOLUTION: First To find reactions As the load is unsymmetrical the reactions are not equal. The load applied is nearer to support A and hence … Read more
Q. A simply supported beam of 8 m long has a point load of 10 kN at its centre. Determine the reactions of supports and maximum bending moment. SOLUTION: The loading given on the simply supported beam is symmetrica Hence R{A} = R{B} = 10/2 = 5kN BMD (BENDING MOMENT DIAGRAM ) M{A} = M{B} … Read more
Q. A simply supported beam of span 4 m carries a point load of 10 kN at its centre. Draw SFD and BMD. Find max Shear force and Вending moment SOLUTION: First To find reactions As the load is symmetrical, the load shared by the two supports are equal. Hence R{A} = R{B} = 10/2 … Read more
Q. A simply supported beam of span 6m carries a central point load of 8 kN. Draw SFD and BMD SOLUTION: As the beam is symmetrically loaded, hence RA =R B = Total load /2 = 8/2 = 4 kN SFD (SHEAR FORCE DIAGRAM) FA =4 kN(from A to C it is 4 kN) FC … Read more
Q. A cantilever beam 5 m long is loaded with udl of 3kN / m over 2 m length from free end. Point load of each 5 kN are acting at 2 m and 4 m respectively from fixed end. Draw the shear force and bending moment diagrams. Mention max SF and BM values. SOLUTION: … Read more
Q. Draw shear force and bending moment diagrams of cantilever beam loaded as shown in figure. SOLUTION: SFD (SHEAR FORCE DIAGRAM) Total load = 4 + 5 + 3 + 4 × 2 = 20kN F{E} = 0 F{D} = 11kN(4 × 2 + 3 = 11kN) F{C} = 16kN(5 + 3 + (4 × … Read more