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Q. A cantilever beam of span 3 m. A udl of 2 kN/m is acting between 1 m to 3 m from fixed end. Draw SFD & BMD.

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SOLUTION: Total load = 2 * 2 = 4kN S.F.D (SHEAR FORCE DIAGRAM) F{A} = 4kN (same between A and C) F{C} = 4kN F{B} = 0kN Max S.F occurs at A = 4kN BMD( BENDING MOMENT DIAGRAM) M{B} = 0 M{C} = – (2 * 2) * 2/2 = – 4kNm M max =M … Read more

Q.A cantilever AB is 6 m long and is fixed at A. It carries point loads of 10 kN, 8 kN and 12 kN at 2 m, 5 m and 6 m respectively from the fixed end. Draw SFD and state max SF

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SOLUTION: SHEAR FORCE DIAGRAM FA =30 kN (same in between AC) FC (just left of C) = 30 kN FC (just right of C) = 20 kN FD (just left of D) = 20 kN FD (just right of D) = 12 kN FB =(just left of B) = 12 kN FB (just right of … Read more

A Cantilever beam of Span 3m carries two point loads Of 10 kN and 20kN are acting at Om and 2m From free End. Draw SFD AND BMD

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Q.A Cantilever beam of Span 3m carries two point loads Of 10 kN and 20kN are acting at Om and 2m From free End. Draw SFD AND BMD SOLUTION: Total load = 30 + 10 = 30kn SFD F{A} = 30kn( same upto AC) FC =( Just left of c) = 30KN FC = (Just … Read more

A closed -traverse is  conducted in anticlockwise direction with Five stations A, B, C, D, and E in the form of a regular Pentagon. If the F.B Of AB is  45°00′, find the F. B’s of Other sides

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A closed -traverse is  conducted in anticlockwise direction with Five stations A, B, C, D, and E in the form of a regular Pentagon. If the F.B Of AB is  45°00′, find the F. B’s of Other sidesA closed -traverse is  conducted in anticlockwise direction with Five stations A, B, C, D, and E in … Read more

The following table gives the fore and back bearings of sides of a closed compass traverse. Test and correct the values of the bearings for local attraction 

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The following table gives the fore and back bearings of sides of a closed compass traverse. Test and correct the values of the bearings for local attraction  Line fore bearing Back bearing AB N 55°00′ E S 54°00′ W BC S 67° 30′ E N 66°00′ W CD S 25°00′ W N25°00’E DE S77°00′ W … Read more

plot the following cross staff Survey of a field ABCDEFG and calculate its area in hectares

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plot the following cross staff Survey of a field ABCDEFG and calculate its area in hectares Soultion: show the field ABCDEFG . The calculations of area are listed in the Following table S. NO figure chainage Base offset mean Offset Area Remark  1 ΔAQB o to 200 200 0 to 130 65 13,000  2. Trapezium … Read more

Following figure shown a page in a field book of cross staff survey. Calculate the area enlarged between the stations:

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Following figure shown a page in a field book of cross staff survey. Calculate the area enlarged between the stations:   1. Area of triangle AHD = 1 / 2 x 30 x 22.50 = 337.50 m² 2. Area of Trapezium HDFJ = ( 88.0-30.0) = ( 22.50+33.80/ 2 ) = 1632 . 70m² 3. … Read more

Q. A Survey line ABDE intersects a building between Band D. To overcome the obstacle a perpendicular BC 90 m long, is set out at B. From C, two lines CD and CE are set out at angles 45º and 60 respectively with CB. Find the lengths CD and CE such that points D and E fall on the prolongation of line AB. Also find the obstructed distance BD.

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Q. A Survey line ABDE intersects a building between Band D. To overcome the obstacle a perpendicular BC 90 m long, is set out at B. From C, two lines CD and CE are set out at angles 45º and 60 respectively with CB. Find the lengths CD and CE such that points D and … Read more

A line was measured with a steel tape which is exactly 30 m long at 18°C and found to be 452.3.43 m. The temperature during measurement was 32°C. Find the true length of line Take coefficient of expansion of tape per °C = 0.000117

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1 Q.A line was measured with a steel tape which is exactly 30 m long at 18°C and found to be 452.3.43 m. The temperature during measurement was 32°C. Find the true length of line Take coefficient of expansion of tape per °C = 0.000117 Solution: Given data: Length of tape L = 30m Coefficient … Read more

The distance between the two stations was measured with a 20 m chain and found to be 600 metres. The same was measured with a 30 m chain and found to be 596 metres. If the 20 m chain was 5 cm too short, what was the error in the 30 metre chain?

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1.Q. The distance between the two stations was measured with a 20 m chain and found to be 600 metres. The same was measured with a 30 m chain and found to be 596 metres. If the 20 m chain was 5 cm too short, what was the error in the 30 metre chain? . … Read more