Q. A simply supported beam of span 6 m subjected to a udl of 2 kN/m over the entire span. Find the support reactions.
Q. A simply supported beam of span 6 m subjected to a udl of 2 kN/m over the entire span. Find the support reactions. SOLUTION: Total load= 6 × 2 = 12kN As the given loading is symmetrical hence RA =RB = Total load / 2 = 12/2 = 6kN . Q. … Read more