A simply supported beam of span 4 m carries a udl of 10 kN/m over the entire span and a point load of 10 kN acting at distance of 1m from let end. Find the reactions at supports.

SOLUTION :

Total load = 10 x 4 + 10 = 50

Taking moments about A

RB x 4 = 10 x 1 + ( 10×4 ) 4/2

RB x 4 = 90kN

RB = 90 / 4 = 22.5kN

RA= Total load – RB

RA= 50 – 22.5 = 27.5kN

( or )

Taking moment about B

RA x 4. = 10×3 + (10×4) 4/2

RA x 4 = 11OKN

RA= 110 / 4 = 27.5kN

RB = Total load – 27.5kN

RB= 50 – 27.5 = 22.5kN