A simply supported beam of 4 m span carries a point load of 10kN at its centre. Find the reactions at the supports.
The load applied symmetrical.
Hence
RA = RB = Total load/2
= 10 / 2
=5kn
A simply supported beam of 4 m span carries a point load of 10kN at its centre. Find the reactions at the supports.
The load applied symmetrical.
Hence
RA = RB = Total load/2
= 10 / 2
=5kn