A cantilever beam of span 4 m, carries three point loads of 3 kN, 5 kN and 6 kN are acting at 1 m, 2 m and 3 m respectively from fixed end. Draw B.M.D.

Q.A cantilever beam of span 4 m, carries three point loads of 3 kN, 5 kN and 6 kN are acting at 1 m, 2 m and 3 m respectively from fixed end. Draw B.M.D.

Solution:

Total load = 3 + 5 + 6 = 14kN
SFD

F{B} = 0

Fc = (just left of C) = 14 kN

F{c} = (just right of C)= 11kN

F{D} = (just left f D)= 11kN

FD = (just right f D)= 6kN

F{E} = (just left f E)= 6kN

F{E} = (just right of E) =0 kN

F max =14 kN occurs in between A & C

BMD

M{B} = 0

M{E} = 0

M{D} = – 6 * 1 = – 6kNm

M{C} = – 6 * 2 – 5 * 1 = – 17kNm

M max =MA = -6*3 -5*2 -3*1= -31 kNm

Max B.M. occurs at A = – 31 kNm