A beam of length 8 m carries two point loads of 60 kN and 90 kN are placed at a distance of 3 m and 5 m from the left hand support. Find the reactions.

SOLUTION :

Total Load = 60+90= 150kN

Taking moments about A

RB×8 = 60×3 + 90 x 5

RB x 8 = 630

RB = 630/8 = 78.75kN

RA = Total load – RB

RA= 150 – 78.75  = 71.25kN

( or )

Taking moments about B

RA x 8 = 90×3 + 60×5

RA x.8 = 570

RA= 570/8  = 71.25kN

Both methods are we gave Same answer

Result: RA = 71.25kN.  RB= 78.75kN