Q. Draw the S.F and B.M diagrams for the cantilever beam shown in figure.

Q. Draw the S.F and B.M diagrams for the cantilever beam shown in figure.

SOLUTION:
Total load = 25+18+10×4 = 83 kN

SFD (SHEAR FORCE DIAGRAM )
FA = 83 kN (same in AC)
FC= (just left of c) = 83 kN
FC =(just right of (c)=58kN
FD = 58kN
FE =( just left of E) = 38 kN
FE (just right of E) = 20 kN
FB=0
Max Shear Force occurs at A = 83 kN ( same in AC)

BMD ( BENDING MOMENT DIAGRAM)
MB=0
ME= -( 10×2) 2/2 = -20KNm
MD = – 18×2 – ( 10× 4) 4/2 = – 116KNm
MC = -18×4 -( 10 × 4 ) (4/2+2) = – 232KNm
MA = – 25 × 2 – 18×6 – (10×4) (4/2+4)
= -50 -108 -240
=-398 KNm
Max BM occurs at A= -398 kNm

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