Q. A cantilever beam of span 4 m carries a udl of 10 kN/m upto a distance of 2 m from fixed end and two point loads of 20 kN and 30 kN placed at a distance of 0 m and 1m from the free end respectively. Draw SFD and BMD.

by

Q. A cantilever beam of span 4 m carries a udl of 10 kN/m upto a distance of 2 m from fixed end and two point loads of 20 kN and 30 kN placed at a distance of 0 m and 1m from the free end respectively. Draw SFD and BMD. 

SOLUTION:

Total load (10×2) +30+20= 70 kN

S.F.D (SHEAR FORCE DIAGRAM)
FD = 50 kN ;                                      FC = 50kN (just left of C)
FC=20kN (Just right of C)
FB=20KN (max value)

BMD ( BENDING MOMENT DIAGRAM)
MB=0
MC= -20×1= -20kNm
MD= – 30×1 – 20 ×2 =-70kNm
Mmax = MA= -(10×2)2/2 – 30×3 – 20×4
= -20 – 90 – 80 = -190 KNm
Max B.M occurs at Fixed end A = M{max}= -190kNm

 

Leave a Comment