Skip to content
Q. At a point of layer of oil, the shear stress is 0.2 N/m² and velocity gradient is 0.25 m/sec/m. Calculate the coefficient of dynamic.
SOLUTION:
Shear stress τ= 0.2N / (m ^ 2)
Velocity gradient, (dv)/(dy) =0.25 m/sec/m
From the relationship,
τ=μ * dv/dy
0.2 = μ * 0.25
μ = 0.8N -sec/m^ 2
coefficient of dynamic viscosity, μ= 0.8N -sec/m^ 2 .
Q. At a point of layer of oil, the shear stress is 0.3 N/m² and velocity gradient is 0.30 m/sec/m. Calculate the coefficient of dynamic.
SOLUTION:
Shear stress τ= 0.3N / (m ^ 2)
Velocity gradient, (dv)/(dy) =0.30 m/sec/m
From the relationship,
τ=μ * dv/dy
0.3 = μ * 0.30
μ = 1 N -sec/m^ 2
coefficient of dynamic viscosity, μ= 1 N -sec/m^ 2 .
Q. At a point of layer of oil, the shear stress is 0.4 N/m² and velocity gradient is 0.40 m/sec/m. Calculate the coefficient of dynamic.
SOLUTION:
Shear stress τ= 0.4N / (m ^ 2)
Velocity gradient, (dv)/(dy) =0.4 m/sec/m
From the relationship,
τ=μ * dv/dy
0.4 = μ * 0.40
μ = 1 N -sec/m^ 2
coefficient of dynamic viscosity, μ= 1 N -sec/m^ 2 .
Q. At a point of layer of oil, the shear stress is 0.5 N/m² and velocity gradient is 0.50 m/sec/m. Calculate the coefficient of dynamic.
SOLUTION:
Shear stress τ= 0.5N / (m ^ 2)
Velocity gradient, (dv)/(dy) =0.50 m/sec/m
From the relationship,
τ=μ * dv/dy
0.5 = μ * 0.50
μ = 1 N -sec/m^ 2
coefficient of dynamic viscosity, μ= 1 N -sec/m^ 2 .
