Q.A simply supported beam of span 6 m. It is carrying 2 kN, 4 kN and 6 kN at 1 m, 3 m and 5 m from the LHS. Calculate the reactions.

SOLUTION:

To find reactions
Total load = 2 + 4 + 6= 12 kN
Taking moments about A
RB×6=2×1+4×3+6×5
= 2+12+ 30 = 44
RB= 44 /6 =7.33kN
RA = Total load – RB
=12 – 7.33 = 4.67kNm
(OR)
Taking moments about B
RA × 6 = 6×1 + 4×3 + 2×5
=6+12+10=28kN
RA= 28/6 =4.67kN