Q. Two point loads of 2kN act at 1/3rd span points on a simply supported beam of span 6 m. Sketch the BMD and state the position of the beam where the B.M is constant and maximum.

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Q. Two point loads of 2kN act at 1/3rd span points on a simply supported beam of span 6 m. Sketch the BMD and state the position of the beam where the B.M is constant and maximum.

SOLUTION:

As the given loading on the beam is symmetrical. Hence
R{A} = R{B} = 4/2 = 2kN
M{A} = M{B} = 0
M{C} = M{D} = 2 × 2 = 4kNm
The B.M is constant in between CD and is equal to 4 kNm.
Max BM occurs in between C and D and is equal to 4 kNm

 

 

Q. Two point loads of 4 kN each act at 1/3 span points on simply supported beam of span 6 m. Sketch the BMD

SOLUTION:

The given loading on the beam is symmetrical Hence R{A} = R{B} = (4 + 4)/2 = 4kN

BMD (BENDING MOMENT DIAGRAM)
M{A} = M{B} = 0
M{C} = 4 × 2 = 8 kNm
M{D} = 4 × 2 = 8 kNm
Max BM occurs in between C and D and its value e = 8 kNm

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