Q.A reinforced concrete beam 300 mm wide by 550 mm overall depth is reinforced with 4 bars of 20mm diameter at an effective depth of 500 mm. Using M 20 grade concrete and Fe 415 steel, estimate the moment of resistance of the section.

Q. A reinforced concrete beam 250 mm wide by 475 mm overall depth is reinforced with 3 bars of 16mm diameter at an effective cover of 50 mm. Using M 20 grade concrete and Fe 415 steel, find the depth of neutral axis.

SOLUTION:

WIDTH b= 250mm

EFFECTIVE DEPTH d = 475 – 50 = 425mm

AREA OF TENSION STEEL Ast = 3× π /4 ×16² = 603.2mm²

1. PERMISSIBLE STRESSES.     

σcbc = 7 N/mm²

σst = 230 N/mm²

2. MODULAR RATIO 

m = 280/3σcbc

    = 280/ 3×7

    = 13.33

3. DEPTH OF NEUTRAL AXIS 

Equating the moments of areas of compression and tension zone about the neutral axis

          bn²/2= m.Ast(d – n)

         1/2×250 n² = 13.33 x 603.2 (425 – n)

          125 n² = 3.42×10⁶  –  8040.7 n

          n² +64.33 n – 27360= O

          n= (- 64.33 + √64.33² +4 × 27360)/2

          n = 136.3 mm

DEPTH OF NEUTRAL AXIS n = 136.3 mm

 

 

Q.A reinforced concrete beam 300 mm wide by 550 mm overall depth is reinforced with 4 bars of 20mm diameter at an effective depth of 500 mm. Using M 20 grade concrete and Fe 415 steel, estimate the moment of resistance of the section.

SOLUTION:

WIDTH b= 300mm

EFFECTIVE DEPTH d = 550 – 50 = 500mm

AREA OF TENSION STEEL Ast = 4× π /4 ×20² = 1256.6mm²

1. PERMISSIBLE STRESSES.     

σcbc = 7 N/mm²

σst = 230 N/mm²

2. MODULAR RATIO 

•m = 280/3σcbc

    = 280/ 3×7

    = 13.33

•Critical depth of neutral axis  NC = 0.289d

3. DEPTH OF NEUTRAL AXIS 

Equating the moments of areas of compression and tension zone about the neutral axis

          bn²/2= m.Ast(d – n)

         1/2×300 n² = 13.33 x 1256.6 (500 – n)

      150 n² = 8.375×10⁶  –  16750.5 n

          n² +111.7 n – 55840= O

          n= (- 111.7 + √111.7² +4 × 55840)/2

          n = 187 mm

critical depth of neutral axis Nc= 0.289×500 = 144.5mm

since n > nc, the section’s is over Reinforced

4. MOMENT OF RESISTANCE

MR =  1/2σcbc b.na (d-na/3)

       = 1/2 x7×300×187 (500-187/3)

       =85.84×10 N-mm

    MOMENT OF RESISTANCE = 85.84 kNm

 

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